# Aluminium Hydroxide as Amphoteric Substance

[SOLVED] Aluminium Hydroxide as Amphoteric Substance

## Homework Statement

Aluminium hydroxide is an amphoteric substance. It can act as either a Bronsted-Lowry base or a Lewis acid. Write a reaction showing $$Al(OH)_{3}$$ acting as a base toward $$H^{+}$$ and as an acid toward $$OH^{-}$$.

## Homework Equations

I know that amphoteric means the substance can act both as a base and as an acid. I also know that, to be a Bronsted-Lowry base, the substance needs to be a proton acceptor and to be a Lewis acid, an electron-pair acceptor.

## The Attempt at a Solution

My biggest problem is that I'm not sure what they really ask. Since it mentions that aluminium hydroxide is an amphoteric substance, does that mean it reacts with itself? If yes, then I'm clueless. If not, then I attempted the following:

$$Al(OH)_{3}+H^{+}\rightarrow Al^{3+}+3H_{2}O$$

and

$$Al(OH)_{3}+OH^{-}\rightarrow Al(OH)_{4}$$

However, my attempt is very much "gazing in my crystal ball" kind of science since it isn't based on anything I know but rather on a lot of unfounded assumptions and shooting in the dark which is why I need assistance phyz

Borek
Mentor

Your reactions - while not that far from the correct answer - ar far from being balanced Your reactions - while not that far from the correct answer - ar far from being balanced

Oh, yeah...of course...see what happens when you concentrate too hard on tex This better?

$$Al(OH)_{3}+3H^{+}\rightarrow Al^{3+}+3H_{2}O$$

and

$$Al(OH)_{3}+OH^{-}\rightarrow Al(OH)^{-}_{4}$$

and Google you reckon? Mmmmmm... Google here I come! Solved! Thanks Borek! Three thumbs up Just a thought, but could the question be asking for something like this?

$$Al(OH)_{3} + Al(OH)_{3}{+}\rightleftharpoons AlH(OH)_2^+ + AlO(OH)_2^-$$

This is, as the question states, "a" reaction, where Al(OH)3 bevaes in both ways, one accepting a proton, the other an electron pair. Autoionisation?

Its late, I'm tired, and this has kept me busy for too long, so pleeease tell me if im completely wrong :P

Last edited:
Borek
Mentor
These are equilibrium systems, to some extent such reaction will proceed - along many others. So you are not completely wrong.

What I don't like about the reaction is that it may suggest a little bit too much. It may occur, but for sure it will not dominate the solution.