Am i going about this angular acceleration question the right way?

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SUMMARY

The discussion focuses on calculating the average angular acceleration of a wristwatch's second hand, specifically a 0.023 g, 1.0 inch long hand. The average angular acceleration (α) can be derived using the equation av = w/t, where 'w' represents angular displacement and 't' is time. If the second hand moves smoothly, it maintains a constant velocity with no angular acceleration. However, if the watch delivers an impulse every second, the second hand moves 1/60th of 360 degrees each second, necessitating the use of angular kinematics to determine acceleration during the starting and stopping phases.

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Homework Statement


A 0.023 g 1.0 inch long second hand on a wristwatch. Find its average angular acceleration?


Homework Equations


av=w/t


The Attempt at a Solution



so would i just do 0.023 g divided by 1 minute?
 
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this is an oddly phrased question.

If the second hand goes around smoothly, it won't have any acceleration just a constant velocity.

If it's one of those watches that delivers an impulse every second then the hand would move 1/60th of 360 degrees every second. In this case you could use the angular version of the distance equation and solve for a, but you'd have to consider that the second hand goes from 0 to some alpha, then from that alpha back to zero (starting and stopping).

note: (alpha is angular acceleration)
 
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