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## Homework Statement

How much kWh is beeing used to heat 285 liters of water in a water heater from:

1. + 5 °C to + 75 °C

2. + 20 °C to + 75 °C

## Homework Equations

Found this equation:

kWh = (Q*CJ*∆t)/T

## The Attempt at a Solution

Q = liter = 285

Cj = heat capacity = 4,18

∆t = 70 for 1. And 55 for 2.

T = is the time, but I'm not sure what to use here, so I used 3600.

So my answer was:

1. 23,2 kWh

2. 18,2 kWh

I have no clue if this is right or wrong because of the variable T. What is correct here?