Amplify Arduino PWM with LM324 to 0-10V

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To amplify Arduino PWM from 0-5 volts to 0-10 volts using an LM324, a higher voltage supply of about 12 to 15 volts is necessary, as op-amps cannot output more voltage than their supply. Users are advised to explore DC to DC step-up voltage converters to achieve this. It's important to avoid powering devices directly from the Arduino; instead, use the Arduino signal to control an external power source. The output voltage requirement and impedance will depend on the specific application for the 10V output. Proper power management is crucial to ensure reliable operation.
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I am using the LM324 to amplify the signal arduino pwm from 0-5 volts to 0-10 volts, but with the source of 5 volts can not amplify :( ... someone can help me to amplify this signal pwm
 
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an opamp cannot make more volts than you give it as supply , that's all it has to work with. (well except for some special ones with built in voltage boost)
so you'll need to generate about 12 to 15 volts for the opamp's supply pin.

There exists a whole world of DC to DC step up voltage converters
http://www.ti.com/lit/ds/symlink/lm2767.pdf is about the simplest
you could start here for some background
http://www.ti.com/download/trng/docs/seminar/Topic_3_Lynch.pdf
and see this more traditional boost converter
http://www.ti.com/lit/ds/symlink/lm2700.pdf
 
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Thanks guys for fixing the 'necropost'
 
What will you be doing with the 10V output?
That will decide the voltage requirement and output impedance.
 
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Just a note. I would not recommend powering your device off of the arduino.

Pull your power from somewhere else and use signal from the arduino to control your load.

If you use a DC DC converter, the power will be drawn from the ardunio itself.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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