Amplitude and Pressure Wave: Pa Homework

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Homework Help Overview

The discussion revolves around a physics problem related to sound waves, specifically focusing on the amplitude of a pressure wave and its effects on the human ear. The problem involves calculating force and pressure using given parameters such as the area of the eardrum and the oval window.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between pressure, area, and force, with one suggesting the formula F = pressure * area. There is also a question about the correct method for converting units from cm² to m², highlighting the need for careful unit conversion.

Discussion Status

Some participants have provided guidance on unit conversion and the application of relevant formulas. There is an acknowledgment of the initial confusion regarding the problem setup, but a participant expresses confidence after receiving assistance.

Contextual Notes

The original poster expresses uncertainty about how to begin solving the problem and seeks starting advice. There is a mention of homework constraints, as the problem is part of a WebAssign assignment.

bnwchbammer
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Webassign night again!

Homework Statement


During normal conversation, the amplitude of a pressure wave is 0.023 Pa.
(a) If the area of the eardrum is 0.56 cm2, what is the force on the eardrum?
N

(b) The mechanical advantage of the three bones in the middle ear is 1.5. If the force in part a is transmitted undiminished to the bones, what force do the bones exert on the oval window, the membrane to which the third bone is attached?
N

(c) The area of the oval window is 0.026 cm2. What is the pressure increase transmitted to the liquid in the cochlea?
Pa



Homework Equations


I'd assume I'd be using dB=20log(P/P) But I'm not sure how to apply that to any of these equations.


The Attempt at a Solution


Can't even figure out where to start. I'm sure with some starting advice, or at least how to solve the first part I could figure it out.
 
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Maybe you could start with F = pressure * area
 
well, to convert cm^2 to m^2 do I have to do anything special besides just dividing by 100?
 
bnwchbammer said:
well, to convert cm^2 to m^2 do I have to do anything special besides just dividing by 100?

You have to do more than divide by 100. If it was converting cm --> m dividing by 100 would be ok.

Think of it this way in terms of multiplication- You want to cancel the units until you have m^2.

So-

1cm^2 *(1m^2)/(100^2 cm^2) = .0001 m^2.

So you know there are 100 cm in a meter. So if everything is squared, that must mean that there are 100^2 cm^2 in a m^2. So as you see above, when looking at the units, the cm^2's cancel out and you are left with m^2.
 
Should'a been able to figure that out, but got it now. 100% on webassign, all right. Thanks for helpin me out guys.
 

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