Amplitude of velocity (Travelling wave)

In summary, the given wave traveling along a long string has the form y(x,t) = 20sin(3x-2t), where x is in metres and t is in seconds. To find the amplitude of the velocity of any particle on the string, the partial derivative of y with respect to t is taken, resulting in -40cos(3x-2t). The amplitude of the velocity is then determined to be -40 m/s or 40 m/s depending on whether the absolute value is taken.
  • #1
Alex_Neof
41
2

Homework Statement


A wave traveling along a long string has the form:

##y(x,t) = 20sin(3x - 2t),

## where ##x## is in metres and ##t## is in seconds.

Find the amplitude of the velocity of any particle of the string.

2. Homework Equations


Do I just find ##\frac {\partial y}{\partial t} ## ?

The Attempt at a Solution



So ##\frac {\partial y}{\partial t} = -40cos(3x - 2t) ##, therefore the amplitude of the velocity of any particle of the string is ##-40 m/s##. Absolute value ##40 m/s##.
Or is it more involved?
 
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  • #2
Your work looks good to me. However, the units for y are not given. 20 m seems like a very large amplitude for a wave on a string. :wideeyed:
 
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  • #3
ahaha !. The :wideeyed: is making me laugh. Yeah the question didn't give the units for y. Thanks TSny.
 
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