Amplitude of velocity (Travelling wave)

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SUMMARY

The wave traveling along a string is described by the equation y(x,t) = 20sin(3x - 2t), where x is in meters and t is in seconds. The amplitude of the velocity of any particle of the string is calculated by taking the partial derivative with respect to time, yielding ∂y/∂t = -40cos(3x - 2t). The absolute value of the amplitude of the velocity is confirmed to be 40 m/s. The discussion highlights a potential oversight regarding the units of y, suggesting that 20 m may be an unusually large amplitude for a wave on a string.

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Alex_Neof
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Homework Statement


A wave traveling along a long string has the form:

##y(x,t) = 20sin(3x - 2t),

## where ##x## is in metres and ##t## is in seconds.

Find the amplitude of the velocity of any particle of the string.

2. Homework Equations


Do I just find ##\frac {\partial y}{\partial t} ## ?

The Attempt at a Solution



So ##\frac {\partial y}{\partial t} = -40cos(3x - 2t) ##, therefore the amplitude of the velocity of any particle of the string is ##-40 m/s##. Absolute value ##40 m/s##.
Or is it more involved?
 
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Your work looks good to me. However, the units for y are not given. 20 m seems like a very large amplitude for a wave on a string. :wideeyed:
 
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ahaha !. The :wideeyed: is making me laugh. Yeah the question didn't give the units for y. Thanks TSny.
 

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