An ideal fluid flows through a pipe with radius R with flow speed v

[nothing123]

An ideal fluid flows through a pipe with radius R with flow speed v. If the pipe splits up into three separate paths, each with radius (R/2), what is the flow speed through each of the paths?

Would we just use the flow rate equation giving a flow speed of 4v in each of the paths? Does the fact that it split up into three have anything to do with it?

 

[LowlyPion]

You have a volume of fluid flowing through an area.

That times Velocity is the volume passing that point.

The volume has to go somewhere, so ...

A*V_in = ∑ AV_out

R²*V_in = 3*(R²/4)*V_out

 

[nothing123]

Thanks.