An intro to real analysis question. eazy?

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To show that g is the unique inverse of the bijection f, it is necessary to demonstrate that g satisfies the conditions of an inverse function. Since f is a bijection, it has an inverse f^-1 that maps B back to A. The equations f(g(x)) = x for all x in B and g(f(x)) = x for all x in A imply that g must be the unique argument a for which f(a) = x. Therefore, g is defined for all arguments and must equal f^-1, confirming its uniqueness as the inverse function. Proving the uniqueness of g follows from these definitions and conditions.
eibon
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Homework Statement



Let f : A -> B be a bijection. Show that if a function g is such that f(g(x)) = x for
all x ϵ B and g(f(x)) = x for all x ϵ A, then g = f^-1. Use only the definition of a
function and the definition of the inverse of a function.


Homework Equations





The Attempt at a Solution


well since f is a bijection then there exist an f^-1 that remaps f back to A and since g does that then g is the unique inverse of f, or something like that please help I am not very good that this stuff
 
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Yes, you only need to prove uniqueness of an inverse function. If f(g(x))=x, then g(x) must be the unique argument a for which f(a) = x. And so, this condition completely defines g for all the arguments. g is then obviously equal to f-1.
 
thanks losiu for your response.
but how do you prove that it is the unique inverse?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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