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An object moves uphill in a potential

  1. Dec 6, 2009 #1
    an object moves "uphill" in a potential

    [tex]=-\int_{1}^{2}\nabla\mbox{U}\cdot\mbox{dr}\ [/tex]

    [tex]=-\int_{1}^{2}\mbox{dU}[/tex]

    How can this be?

    Any help would be appreciated. Thank you
     
  2. jcsd
  3. Dec 6, 2009 #2

    Redbelly98

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    Re: Work

    This says, essentially, that if an object moves "uphill" in a potential, the work done on the object is negative and so it will have less kinetic energy (move slower) when it moves towards a higher potential.
     
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