- #1

Logarythmic

- 281

- 0

[tex]V(x)=D(e^{-2ax}-2e^{-ax})[/tex].

I'm supposed to obtain the expressions for x as a function of time separately for the cases that the total energy E is positive, zero or negative.

I have used

[tex]\frac{1}{2}m\dot{x}^2 + V(x) - E = 0[/tex]

and got the integral

[tex]\int \sqrt{\frac{m}{2(E-V(x))}}dx[/tex]

to solve.

First, is this a correct method?

Second, how do I solve this integral?