Analyzing the Energy Spectrum of Two Identical Particles

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SUMMARY

The discussion centers on deriving the energy spectrum of two identical particles using the Hamiltonian formalism. The Hamiltonian is expressed as H(p,x) = H(p₁,x₁) + H(p₂,x₂), where H(p,x) = (p²/2m) + (1/2)mω²x². The center of mass (CM) Hamiltonian is derived as H(R,r) = (P_R²/2M) + (P_r²/2μ) + (Mω²R²/2) + (μω²r²/2), with μ = m/2 and M = 2m. The energy spectrum can be obtained by considering the wave function ψ(x₁,x₂) = u₁(x₁)u₂(x₂) and the relation E = ℏω.

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Homework Statement


Two identical particles are descibed by:
[itex]H(p,x)= H(p_{1},x_{1})+H(p_{2},x_{2})[/itex]
where
[itex]H(p,x)=\frac{p^{2}}{2m}+\frac{1}{2}m\omega^2x^2[/itex]

Separate to CM, obtain energy Spectrum. Show it agrees with:

[itex]H\psi (x_{1},x_{2}) = E\psi (x_{1},x_{2})[/itex]
with
[itex]\psi (x_{1},x_{2}) = u_{1}(x_{1})u_{2}(x_{2})[/itex]

Discuss degeneracy.



The Attempt at a Solution



I got the CM hamiltonian to be:

[itex]H(R,r) = \frac{P_{R}^{2}}{2M} + \frac{P_{r}^{2}}{2\mu}+\frac{M\omega^{2} R^{2}}{2}+ \frac{\mu \omega^{2} r^{2}}{2}[/itex]

where [itex]\mu = \frac{m_{1}m_{2}}{m_{1}+m_{2}}=\frac{m}{2}[/itex]

and [itex]M=2m[/itex]
[itex]R=\frac{x_{1}+x_{2}}{2}[/itex]
[itex]r=(x_{2}-x_{1})[/itex]

Not sure how to get the energy spectrum since I don't know the wavefcn.
Any suggestions?
 
Last edited:
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Maybe you should take into account [tex]E = \hbar \omega[/tex] or something like that.
 

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