Why Does Andromeda's Wavelength Calculation Differ from Hubble's Law?

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SUMMARY

The discussion centers on the calculation of the wavelength of light from the Andromeda galaxy, highlighting the differences between observed values and those predicted by Hubble's Law. The formula used for calculating redshift, z = ∆λ/λ0 and z = v/c, reveals that Andromeda exhibits a blue shift, resulting in a wavelength value smaller than λ0. In contrast, applying Hubble's Law yields a greater wavelength value, illustrating the impact of gravitational interactions within local galaxy groups that prevent adherence to Hubble's predictions.

PREREQUISITES
  • Understanding of redshift and blueshift in astrophysics
  • Familiarity with Hubble's Law and its implications
  • Knowledge of the formula z = ∆λ/λ0 and z = v/c
  • Basic concepts of gravitational interactions between galaxies
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  • Research the implications of gravitational interactions on galaxy velocities
  • Study the effects of blueshift and redshift on astronomical observations
  • Explore advanced calculations involving redshift in cosmology
  • Learn about the limitations of Hubble's Law in local group dynamics
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Astronomers, astrophysics students, and anyone interested in the dynamics of galaxy movements and the implications of redshift and blueshift in observational astronomy.

Orion78
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I have calculated the wavelength of a line that would be observed in a spectrum from Andromeda where speed and λ0 were known, using the formula z =∆λ/λ0 and z=v/c. I obtained a value smaller than λ0 because Andromeda display a blue shift. After I calculated the same wavelength pretending that Andromeda obeyed the Hubble relationship and I found a different value, greater than λ0. his is because the blueshift indicates a decrease in wavelengths while the redshift an increase in wavelengths? Thanks!
 
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Yes, that sounds right. We cannot expect relative velocities of galaxies withing a local group to obey Hubble's law because of the mutual gravitational attraction between the galaxies.
 

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