Doppler shift of object in expanding universe

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Homework Help Overview

The discussion revolves around the Doppler shift of light from an object moving away from the observer, specifically focusing on a wavelength of 1.55μm and a distance of 10 megaparsecs. Participants explore the implications of the object's velocity and the resulting frequency shift, questioning the definitions and calculations involved in determining whether the shift is red or blue.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to calculate the frequency from the given wavelength and discuss the implications of their results on the redshift or blueshift of the light. Questions arise regarding the correctness of units and the interpretation of frequency values.

Discussion Status

There is ongoing clarification regarding the calculations and the interpretation of results. Some participants express uncertainty about their frequency calculations and the significance of the values obtained. The discussion reflects a mix of attempts to correct previous errors and confirm understanding of the Doppler effect in the context of an expanding universe.

Contextual Notes

Participants note that the problem's context may overlook local motions of objects, which could affect the interpretation of the results. There is also mention of the potential confusion in the problem's wording regarding the determination of redshift or blueshift.

leroyjenkens
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Homework Statement


What's the doppler shift (Δf) of the object moving away from us if we measure a wavelength of light λ=1.55μm emitted from it and it's at a distance of 10 megaparsecs? And is the object red or blue shifted?
Added information to the problem is for each megaparsec the object is away from us, it's moving 74 km/s faster.


Homework Equations


f=\frac{c}{λ}

f=\frac{\sqrt{1-β}}{\sqrt{1+β}}f_0
For source and receiver receding from each other.

f=\frac{\sqrt{1+β}}{\sqrt{1-β}}f_0
For source and receiver approaching each other. (shouldn't need this one)

β = \frac{v}{c}


The Attempt at a Solution



I find frequency first, by using equation #1, and converting the micrometers of the wavelength to meters. I find it to be 5.1666667x10-15.
Then I plug that into the second equation to find f0, which is 5.1794269x10-15

f0 is larger than f. Does f0 stand for initial frequency? Well, the difference in frequencies is f0-f, which is 1.276x10-17

So I assume that means the frequency was stretched? Which means it was redshifted?
I guess if it was compressed, I would have received a negative number, and that would have meant it was blueshifted?

Thanks.
 
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leroyjenkens said:
I find frequency first, by using equation #1, and converting the micrometers of the wavelength to meters. I find it to be 5.1666667x10-15.
That number has missing units, but as a frequency it is certainly wrong. Is it the inverse value, if you add units?

f0 is larger than f. Does f0 stand for initial frequency?
Right.

So I assume that means the frequency was stretched? Which means it was redshifted?
I guess if it was compressed, I would have received a negative number, and that would have meant it was blueshifted?
Right.


By the way: 10 MPc is too close to ignore the local motion of objects. But that is an issue of the problem statement, you can ignore it here.
 
That number has missing units, but as a frequency it is certainly wrong. Is it the inverse value, if you add units?
From the first equation, f ends up with 1/s. Hertz is the unit of frequency, and hertz is 1/s, right? And I just figured out one of the things I did wrong. How the heck I ended up with such a small number from equation 1, I have no idea.

So f is actually 1.935x10^14 and f0 = 1.94x10^14

Which means delta f = 4.78x10^11 s^-1

Since since it's a positive number, that means it's redshifted? Did I fix my mistakes?

Thanks.
 
leroyjenkens said:
So f is actually 1.935x10^14 and f0 = 1.94x10^14

Which means delta f = 4.78x10^11 s^-1
That looks more realistic (and those are the inverse values of the numbers in post 1)

Since since it's a positive number, that means it's redshifted? Did I fix my mistakes?
Right. You don't need the sign to know it is redshifted - it is moving away, so it is redshifted, done.
 
mfb said:
That looks more realistic (and those are the inverse values of the numbers in post 1)

Right. You don't need the sign to know it is redshifted - it is moving away, so it is redshifted, done.

Thanks. Yeah, I knew it was redshifted by the fact that it was moving away, but the way the question is worded, it makes it sound like I need to use the value I obtained to determine whether it was redshifted or blueshifted. Thanks again.
 

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