Angle between the hands of a clock (IWTSE)

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SUMMARY

The discussion centers on the mathematical derivation of the angle between the hands of a clock, specifically addressing the use of the '2n-1' multiplier in the equation. Participants clarify that '2n-1' represents an odd integer, which is crucial for calculating angles such as 90 degrees and 270 degrees, where the hands are perpendicular. The calculations of mπ/2 for m=0, 1, 2, etc., are emphasized to identify the corresponding angles. Ultimately, the correct angle derived from the discussion is confirmed to be 44 degrees.

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  • Understanding of basic trigonometry
  • Familiarity with radians and degrees
  • Knowledge of clock mechanics and hand positions
  • Ability to perform algebraic manipulations
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  • Study the derivation of clock angle formulas
  • Learn about odd and even integers in mathematical contexts
  • Explore the concept of angular displacement in circular motion
  • Practice calculating angles using mπ/2 for various integer values
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Students in mathematics, educators teaching geometry, and anyone interested in understanding the mechanics of clock angles and their calculations.

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Homework Statement
Question: For a conventional clock, how many times does the minute hand make a right angle with the hour hand in one day (between midnight on two consecutive days)?
Relevant Equations
Circle formulae.
IWTSE - Clock Working.jpg


I understand this working all the way up until the '2n-1' part, where n is a positive integer.

I understand that delta theta is 90 degrees (i.e. pi/2 radians), as the hands are at right angles to each other.. I also understand where the angle equations are derived from and why you have to find the difference between them. I just don't know why '2n-1' was chosen as the multiplier for pi/2. Would someone be able to explain this?
 
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Try calculating ##m\frac \pi 2## for ##m=0, 1, 2, \dots##. Which values of ##m## correspond to the angles you're looking for here?
 
vela said:
Try calculating ##m\frac \pi 2## for ##m=0, 1, 2, \dots##. Which values of ##m## correspond to the angles you're looking for here?

Thank you. I now understand that '2n-1' (or '2n+1') is meant to represent an odd integer, since if delta theta = 270 degrees the hands are still perpendicular. I got an answer of 44.5 (or 43.5, depending on the expression used) which rounds to 44, the correct answer.
 

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