Angles between normals at 2 points on a surface

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SUMMARY

The discussion focuses on calculating the angle between normal vectors at two points on a surface defined by a function f(x,y,z). To find the normals at points (x_0, y_0, z_0) and (x_1, y_1, z_1), one must compute the gradients ∇f(x_0, y_0, z_0) and ∇f(x_1, y_1, z_1). The angle between these normal vectors can be determined using the dot product formula: cos⁻¹(∇f(x_0, y_0, z_0)·∇f(x_1, y_1, z_1) / |∇f(x_0, y_0, z_0)||∇f(x_1, y_1, z_1)|).

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  • Understanding of normal vectors in multivariable calculus
  • Familiarity with gradient calculations
  • Knowledge of the dot product of vectors
  • Basic concepts of surface functions in three-dimensional space
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  • Study gradient vector fields in multivariable calculus
  • Learn about the properties of the dot product and its applications
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svishal03
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I have been reading about the normal vector to a point on a surface.

http://mathworld.wolfram.com/NormalVector.html

Can anyone explain if I have normals to 2 points on a surface and I want to compute the inclinations between them, how would one proceed?
 
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svishal03 said:
I have been reading about the normal vector to a point on a surface.

http://mathworld.wolfram.com/NormalVector.html

Can anyone explain if I have normals to 2 points on a surface and I want to compute the inclinations between them, how would one proceed?

Hey svishal03.

What do you mean by inclinations? Do you mean the angle between them?
 
How you determine the angle between normals depends upon the way the surface is given. For example, if you are given f(x,y,z)= constant, the normals at (x_0, y_0, z_0) and (x_1, y_1, z_1) are given by \nabla f(x_0, y_0, z_0) and \nabla f(x_1, y_1, z_1). And, of course, the angle between those two vectors is given by their dot product: cos^{-1}(\vec{u}\cdot\vec{v}/|\vec{u}||\vec{v}|).
 

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