Angluar Speed and Moment of Inertia

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SUMMARY

The discussion centers on calculating the moment of inertia of a flywheel after 100 joules of work is applied, increasing its angular speed from 60 rpm to 180 rpm. The relevant equations include Angular Acceleration = (Radius)(Angular Velocity)^2 and I = 1/2MR^2. Participants express confusion about applying work to these formulas and suggest using energy conservation principles, specifically K_{r0} + W = K_{r}, where K_r = 1/2Iω². Additionally, a secondary problem regarding the initial speed of a falling ball is discussed, with recommendations to use the kinematic equation for vertical displacement.

PREREQUISITES
  • Understanding of angular motion and moment of inertia
  • Familiarity with energy conservation principles in physics
  • Knowledge of kinematic equations for vertical motion
  • Basic grasp of angular velocity and acceleration concepts
NEXT STEPS
  • Study the derivation and application of the moment of inertia formula I = 1/2MR²
  • Learn about energy conservation in rotational dynamics
  • Explore the kinematic equations for projectile motion, particularly vertical displacement
  • Investigate the relationship between angular acceleration and angular velocity
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to angular motion and energy conservation.

brad_i2001
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Homework Statement



When 100 joules of work is done upon a flywheel, it's angular speed increases from 60 rpm to 180 rpm. What is the moment of inertia?

Homework Equations



Angular Acceleration = (Radius)(Angular Velocity)^2
I= 1/2MR^2
Work=FD

The Attempt at a Solution



To be honest, I am not sure how to apply work to either of the formulas. I know the Angular Acceleration is 120 rpm, but still do not know the radius. Would you substitute 120 for angular velocity and 180 for angular Acceleration? This would give the radius, and the mass would be found by the W=FD formula.

-Thanks!

Homework Statement



A 10 g ball is thrown straight down from a height of 2 meters. If the ball strikes the floor at a speed of 7.5 m/sec, what is the initial speed of the ball?

Homework Equations



dy= -2
vi=?
dx=(vx)(t)
dy=-1/2gt^2

The Attempt at a Solution


That is as far as I have gotten. I am, once again, not sure how to apply the formula to the given information. I am sure this one is much easier than the last, but I still need help.

-Thanks!
 
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You can do this in terms of energy. K_{r0} + W = K_{r} where K_r = \frac{1}{2}I\omega^2. Also, just as a side note, centripetal acceleration is r\omega^2, angular acceleration is \frac{d\omega}{dt}.
 
Thank you SO Much! Everything worked! Do you have any suggestions for the falling ball question? Thanks Again!
 
For the falling ball problem, use the complete kinematic equation for vertical displacement:

y = y_0 + v_0 t - (1/2) g t^2
 

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