Angular acceleration calculation

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The calculation for angular acceleration using the formula Torque = I * α was performed with a torque of 225 Ncm and a moment of inertia of 0.35 kg.cm². The resulting angular acceleration was calculated as α = 225 Ncm / 0.35 kg.cm², yielding a value of 64285.7/s². However, there was confusion regarding the correctness of this answer, with suggestions that it might involve too many significant figures. Participants noted they arrived at the same numerical solution but questioned what might differ in the final presentation of the answer. The discussion highlights the importance of clarity in significant figures and the final solution format.
robax25
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Homework Statement
Angular acceleration calculation
Relevant Equations
T=I.α
Torque=225 Ncm

Torque=α*0.35 kg.cm²

α=225Ncm/0.35kg.cm²

=225 kg.m/s²*cm/0.35kg.cm²
=225*100/.35s²
=64285.7/s²
but the answer is wrong
 
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robax25 said:
Homework Statement:: Angular acceleration calculation
Relevant Equations:: T=I.α

Torque=225 Ncm

Torque=α*0.35 kg.cm²

α=225Ncm/0.35kg.cm²

=225 kg.m/s²*cm/0.35kg.cm²
=225*100/.35s²
=64285.7/s²
but the answer is wrong
Maybe too many significant figures in the answer? I get the same answer as you.
 
I get the solution.
 
robax25 said:
I get the solution.
What was different in the final solution?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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