Angular acceleration for one gear to another

[dumbdumNotSmart]

Homework Statement

Gear r has angular acceleration of a magnitude of .2 rads^{-2}(counterclockwise) and is resting at t=0s . p is a cylinder welded to R (concentric). r applies torque to R, these do not slip or slide. A mass m hangs from a string which is attached to p. This string is not elastic nor does it have mass. The gears and cylinder are massless, and the mass has no effect on the acceleration of the gears.
r=5cm ; R=20cm ; p=10cm ; acceleration of r =.2 rads^{-2}

a) Find distance traveled by m after 10 seconds (t=10s)
b) Find velocity of m at said postion (t=10s)

Homework Equations

w=v/r ; radians traveled = .5(Ang. Accel.)t^2 (omitting initial conditions) ; radians = d/r ;
w=(ang. acc.)t (omitting initial conditions)

The Attempt at a Solution

I'd much rather not go through the tedious task of rewriting all my work in a format I am not accustomed to. You can see all the above information in another forum where I posted the same question. For the sake of time, here is http://physics.stackexchange.com/questions/209973/how-do-you-find-the-longitude-travelled-by-a-string-hooked-to-a-concentric-cylin?noredirect=1#comment449514_209973 and formatted.
Although I managed to acquire what seemed like reasonable answers, they differ to the answer key's ( a. d=83.3cm b. v=25cm/s)
I got 25cm for m's displacement and 5 cm/s velocity.

 

[gneill]

Your results look fine to me. Perhaps the problem's given values were tinkered with to "refresh" the question, while the answer key was not updated.

You could take a screen snip of your work and post the image to conform to our rules that you must show your work:

 

[dumbdumNotSmart]

Your results look fine to me. Perhaps the problem's given values were tinkered with to "refresh" the question, while the answer key was not updated.

You could take a screen snip of your work and post the image to conform to our rules that you must show your work:

Alright, I´ll take your word for it. I had been suspecting this for some time now. Thank you so much.