1. The problem statement, all variables and given/known data 1) A solid cylinder of mass M = 1.54 kg and radius r = 0.100 m pivots on a frictionless bearing. A string wrapped around the cylinder pulls downward with a force F that equals the weight of a 0.590 kg mass, i.e., F = 5.782 N. Calculate the angular acceleration of the cylinder. 2)If instead of applying the force F, a mass m = 0.590 kg is hung from the string, what is the angular acceleration of the cylinder? 2. Relevant equations 3. The attempt at a solution I found the answer to 1) to be 75.1 rad/s^2. For 2) I have been doing this: m*g*r = T angaccel = t/l Inertia moment for a solid cylinder = 1/2mr^2 angaccel = t / 1/2mr^2 using my numbers that gives me: (.5782)/(.5*1.54*.1^2) = 75.091 rad/s^2 This is wrong. I have tried 8 times now on the same question and cannot get it, any help?