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A Jeweler, whose near point is 40.0cm from his eye, is using a magnifying glass to examine a gold ring. The lens of the magnifying glass has a focal length of 5.00cm ( part C) Determine the angular magnification of the magnifying glass when the virtual image of the ring is located 165 cm from the lens.
1/f = 1/do + 1/di
M = (1/f - 1/q)N.P.
[(1/5) - (1/165)]40cm = 7.76cm (right answer is 8.24 centimeters ***edit NOT meters. just cm I am just tired and almost done my last exam*** ) and i can't figure out how to get it
1/f = 1/do + 1/di
M = (1/f - 1/q)N.P.
[(1/5) - (1/165)]40cm = 7.76cm (right answer is 8.24 centimeters ***edit NOT meters. just cm I am just tired and almost done my last exam*** ) and i can't figure out how to get it
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