Angular momentum and eccentricity

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SUMMARY

The relationship between angular momentum and orbital eccentricity is established through specific formulas in celestial mechanics. The angular momentum (L) can be expressed as L = √(a(1-e²)/(m₁+m₂)), where 'a' is the semi-major axis, 'e' is the eccentricity, and 'm₁' and 'm₂' are the masses involved. Additionally, the energy of the system is given by E = -G(M+m)/(2a), leading to the relationship e² = 1 - (c/a)L², where c = (M+m)/(GM²m³). These equations demonstrate the interconnectedness of these orbital parameters.

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I'm trying to find the relationship between angular momentum and orbital eccentricity but so far I haven't really found anything. I did find an indirect relationship, though, which looked like it should come out to,[tex]L=\sqrt{\frac{a(1-e^{2})}{m_{1}+m_{2}}},[/tex] but I may be completely wrong. Anyone know the correct answer?
 
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Even if you remove as many variables as possible, orbits always have two degrees of freedom, they can be written as semi-major axis and eccentricity. The angular momentum will depend on both, together with the masses and the gravitational constant.

I found this formula at wikipedia:
a6a3c8e287edeb7d9fa7762763bce081.png


The energy is [itex]E = \frac{-G(M+m)}{2a}[/itex]

Therefore, [itex]e^2 = 1-\frac{c}{a} L^2[/itex] with [itex]c=\frac{M+m}{GM^2m^3}[/itex] and [itex]L=\sqrt{\frac{1-e^2}{ca}}[/itex] where c just depends on the masses.
 
Thanks very much.
 

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