1. The problem statement, all variables and given/known data A 1.9kg , 20 cm-diameter turntable rotates at 150rpm on frictionless bearings. Two 480g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. what is the objects angular velocity in rpm right after this event? 2. Relevant equations L=Iω where L is angular momentum, I is the moment of inertia and ω is the angular velocity moment of inertia for a disk rotating about it's center 1/2*m*r^2 3. The attempt at a solution Ok, so it seems like a simple conservation problem, so I tried to solve it like one. I final*ω final = I initial * ω initial ergo ω final = (I initial * ω initial)/ I final convert 150 rpm in rad/s, (150/60)*2[itex]\pi[/itex] =15.71 since the formula for the moment of inertia "I" for a disk rotating about the center is 1/2*m*r^2 I just plug in the values (.5*1.9kg*.1^2m*15.71 rad/s)/ (.5*(1.9+.96kg)*.1^2m) = 10.44 rad/s converting back to rpm (10.44/ 2[itex]\pi[/itex] )*60 = 99.66 rpm rounded to 100 rpm. But this solution is incorrect. What have I done wrong?