- #1
MRMooneyham
- 25
- 0
A small blob of putty of mass m = 7.1 falls from the ceiling and lands on the outer rim of a turntable of radius R and mass M = 7.5 kg that is rotating freely with an angular speed of 1.4 rad/s about its axis. The postcollision angular speed of the turntable-putty system is ____ rad/s.
L = r x p = Iω
this is the only equation i think i need for this problem
As far as i can tell all i would need to do is...
since R is unknown but will be a constant through out the whole problem, i give it a value of 1 for simplicity sake.
the momentum of the turntable before would be, L = (7.5 x 1^2) x 1.4
L= 10.5
since momentum as to be conserved in this problem the end momentum should also be 10.5
10.5 = [(7.5 x 1^2) + (7.1 x 1^2)] x ω
10.5 = 14.6 x ω
10.5/14.6 = ω
.719 = ω
and since this is a online assignment i can try and answer as many times until i get it correct, but i can't think of where i might be going wrong cause it says i have the wrong answer.
I don't need the problem worked out for me per say...just maybe hint at the error or explain where I am going wrong, and thank you for any help
L = r x p = Iω
this is the only equation i think i need for this problem
As far as i can tell all i would need to do is...
since R is unknown but will be a constant through out the whole problem, i give it a value of 1 for simplicity sake.
the momentum of the turntable before would be, L = (7.5 x 1^2) x 1.4
L= 10.5
since momentum as to be conserved in this problem the end momentum should also be 10.5
10.5 = [(7.5 x 1^2) + (7.1 x 1^2)] x ω
10.5 = 14.6 x ω
10.5/14.6 = ω
.719 = ω
and since this is a online assignment i can try and answer as many times until i get it correct, but i can't think of where i might be going wrong cause it says i have the wrong answer.
I don't need the problem worked out for me per say...just maybe hint at the error or explain where I am going wrong, and thank you for any help
)