Angular size of Venus: Is my math correct?

In summary: according to wolfram alpha the current distance to venus is 0.3343 au = 5 * 10^7 kmso the answer would be: 7.738
  • #1
nukeman
655
0
Ok, just trying to figure out the angular size of venus. I have charted and figured out the distance between Earth and Venus at this certain time is: 149,600,000.00km

Now the diameter of Venus is 12104km.

venus angular diameter is: 9.565

so is it 9.565 x 12104/149,600,000

Is that correct?

So the answer would be: 7.738 ?
 
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  • #2
what should this number be (9.565) - because I am sure that's not right.

Anyone?
 
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  • #3
Sorry, that makes no sense.

nukeman said:
venus angular diameter is: 9.565
I see you copied this number from Wikipedia.
Look at the complete figure:
Wikipedia said:
9.565″ – 66.012″
First, there's a ″. It means arc seconds.
Second, that's a range, with 9.565 being the minimum value.
Third, that's actually the result you're asking for, not something to plug into a formula w/o motivation.

Here's how to do it:
Angular diameter = diameter/distance = 12104/149,600,000 =8.091E-5 = 16.69″.
 
  • #4
Ahh, ok.

How did you get 8.091E-5 turned into = 16.69

So, let's say for mars. I need to find the Angular Size

Mars diameter is 6794km, and distance from Earth is: 74,000,000km

It would be: 9.181x10^-05 ? How do I get the angular size from that?
 
  • #5
9.181x10^-05 is a dimensionless angle. There's a "dimension" defined for angles, called "http://en.wikipedia.org/wiki/Radian" ".
Look up the conversion tables.
So you have 9.181x10^-05 rad = 0,00526° = 0.31562' = 18.937''.
That's rad, degrees (°), arc minutes ('), arc seconds ('').
 
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  • #6
Ich said:
9.181x10^-05 is a dimensionless angle. There's a "dimension" defined for angles, called "http://en.wikipedia.org/wiki/Radian" ".
Look up the conversion tables.
So you have 9.181x10^-05 rad = 0,00526° = 0.31562' = 18.937''.
That's rad, degrees (°), arc minutes ('), arc seconds ('').

Great thanks!

so this
9.181x10^-05 rad = 0,00526° = 0.31562' = 18.937''

is that correct calculation (on my part?)

Great, thanks!
 
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  • #7
so does this mean that MARS would be more visable from earth?
 
  • #8
Yes, if your numbers are correct.
 
  • #9
Venus has an average orbital radius from the Sun of 0.72 AU while Mars' is 1.52 AU, which means the minimum distance between Earth and Venus is just 0.28 vs 0.52 AU between Earth and Mars. The very closest approaches are a little bit less less due to their elliptical orbits, but their perihelia don't perfectly coincide so that figure would be a bit of an underestimate. But, as you can see, Venus should look bigger than Mars - BUT because Venus is an interior planet all we see is it's shaded back when the two planets are at their closest. A thin crescent at best. So when it is biggest it is also at it's dimmest and very close to the Sun in the sky, so hard to see.
 
  • #10
nukeman said:
Ok, just trying to figure out the angular size of venus.
I have charted and figured out the distance between Earth and Venus at this certain time is: 149,600,000.00 km
Now the diameter of Venus is 12104km

12,104 / 149,600,000 = 0.00008 radians

the diameter of an eyeball is 2.5 cm (25,000 micrometers)
retinal cone cells are packed 50 per 100 micrometres in the most central fovea
thats 2 micrometer apart
2 / 25,000 = 0.00008 radians

according to wolfram alpha the current distance to venus is 0.3343 au = 5 * 10^7 km
http://www.wolframalpha.com/input/?i=venus

12,104 / 50,000,000 = 0.000242 radians
 
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Related to Angular size of Venus: Is my math correct?

1. How do you calculate the angular size of Venus?

The angular size of Venus can be calculated using the formula: angular size = (diameter of Venus / distance from Earth) x 206265, where the diameter of Venus is in kilometers and the distance from Earth is in kilometers.

2. What is the diameter of Venus in kilometers?

The diameter of Venus is approximately 12,104 kilometers.

3. How far is Venus from Earth?

The distance between Venus and Earth varies depending on their positions in their orbits, but on average, it is approximately 41 million kilometers.

4. What is the angular size of Venus when it is closest to Earth?

The angular size of Venus when it is closest to Earth is about 1 arcminute, which is equivalent to 1/60th of a degree.

5. Can the angular size of Venus change?

Yes, the angular size of Venus can change as it orbits the Sun and its distance from Earth changes. It can also appear larger or smaller depending on atmospheric conditions and the angle at which it is observed.

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