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Angular Speed of a swinging stick

  • Thread starter snowmx0090
  • Start date
  • #1
I having trouble answering this one. I already had to calculate the change in potential energy but am now stuck.

A stick with a mass of 0.168 and a length of 1.00 is pivoted about one end so it can rotate without friction about a horizontal axis. The meter stick is held in a horizontal position and released.
1) As it swings through the vertical, calculate the angular speed of the stick.

I thought I could answer this by using the equation:
(ω_f)^2 = (ω_i)^2 + 2α Δθ
This does not work and I don't know where to go from here.

2) As it swings through the vertical, calculate the linear speed of the end of the stick opposite the axis.
 

Answers and Replies

  • #2
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Have you drawn a picture yet, or are you just guessing that the equation will work? Make a free body diagram, and examine all the forces throughout the equation. This is really just a pendulum. How long do you think it would take the pendulum to go to the other side, and then back again? What do you suppose its period is?
 
  • #3
Doc Al
Mentor
44,882
1,130
snowmx0090 said:
1) As it swings through the vertical, calculate the angular speed of the stick.

I thought I could answer this by using the equation:
(ω_f)^2 = (ω_i)^2 + 2α Δθ
This does not work and I don't know where to go from here.
That equation assumes constant acceleration, which is not the case here. Hint: Consider conservation of energy.
 

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