Angular velocity/acceleration problem

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In the discussion regarding the angular velocity and acceleration of two discs, it is established that disc A, with a diameter of 3D, will have an angular velocity that is one-third that of disc B, which has a diameter of D. Therefore, the correct assertions are that the angular velocity magnitude of A is equal to 1/3 of B, and the angular acceleration magnitude of A is also equal to 1/3 of B. The relationships can be mathematically expressed as 3w_A = w_B and 3α_A = α_B, confirming the proportional differences in both angular velocity and acceleration.

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Suppose disc A and B are spinning against each other without slipping or translating. What can be said about the motion of disc A in terms of B? (select all that apply; if none apply, leave the boxes blank)
Disk A has a diameter of 3D while disk B has a diameter of D

a. Angular velocity magnitude of A will be 3 times greater than B

b. Angular velocity magnitude of A will be equal to B

c. Angular velocity magnitude of B will be 3 times greater than A

d. Angular acceleration magnitude of A will be 3 times greater than B

e. Angular acceleration magnitude of A will be equal to B

f. Angular acceleration magnitude of B will be 3 times greater than A





L= Iw angular momentum = moment of inertia x angular velocity
t=Ia torque = moment of inertia x angular acceleration




Seeing from the question I think at the moment of contact, the velocity would be 0. But if we are looking at angular velocity as a whole, disk A should have 1/3 the speed of disk B. If that's the case then the angular acceleration diffeence would've also been 3 times between A and B. Can someone verify it?
 
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[tex]3w_A = w_B , \ \ \ <br /> 3\alpha_A = \alpha_B[/tex]

there's nothing else
 

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