What is the Angular Velocity of an LP Record?

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The discussion focuses on calculating the angular velocity and period of an LP record, which spins at 33 1/3 rpm. The conversion from rpm to rad/s is discussed, resulting in an angular speed (ω) of approximately 3.49 rad/s. The period (T) is derived using the relationship ω = 2π/T, leading to a calculated period of about 1.80 seconds. Participants confirm their calculations and express satisfaction with their understanding of the equations involved in circular motion. The thread emphasizes the importance of these fundamental concepts in physics.
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Homework Statement



The once-popular LP (long-play) records were 12 inches in diameter and turned at a constant 33(1/3) rpm.
Find the angular speed of the LP in rad/s and its period in seconds.


Homework Equations



1 rpm=((2∏)/60)

The Attempt at a Solution



for ω i got 3.49

I need help with finding its period in seconds, T.
 
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ω=2π/T

One of the basic equations of circular motion, well worth knowing!
 
thank you. could you please let me know if my omega is correct. I just want to make sure. for T i got 1.80
 
Unless we both made some horrible mistake!
 
yayy! thanks! on to the next...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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