Undergrad Annihilation/creation operator question

  • Thread starter Thread starter KevinMcHugh
  • Start date Start date
  • Tags Tags
    Operator
Click For Summary
Annihilation and creation operators increase or decrease the occupation number of particles by one but do not represent physical processes or observables since they are not self-adjoint or unitary. These operators are primarily formal tools in quantum field theory, useful for classifying particle states in Minkowski spacetime. Each particle type has an associated creation/annihilation operator, with free quantum fields being generalized Fourier transforms of these operators. There is a distinction between operators that represent observables in quantum mechanics and those that do not. Understanding this difference is crucial for interpreting their role in quantum field theory.
KevinMcHugh
Messages
32
Reaction score
10
TL;DR
These operators increase/decrease occupation number by one particle. What observable do these operators represent?
I'm just curious what physical processes these operators represent. Since particles are created/destroyed in pairs, do they have to applied twice to describe an actual process?
 
Physics news on Phys.org
KevinMcHugh said:
Summary: These operators increase/decrease occupation number by one particle. What observable do these operators represent?

I'm just curious what physical processes these operators represent. Since particles are created/destroyed in pairs, do they have to applied twice to describe an actual process?
They don't represent physical processes or observables (they're not self adjoint or unitary). They're just formal operators useful in quantum field theory.

Wigner managed to find a way to classify all particle states in Minkowski spacetime. With each type there is an associated creation/annihilation operator and free quantum fields ultimately turn out to be just (generalized) Fourier transforms of them.
 
  • Like
Likes vanhees71, KevinMcHugh and PeroK
Thank you DarMM. I was under the assumption operators represent observables in QM.
 
KevinMcHugh said:
Thank you DarMM. I was under the assumption operators represent observables in QM.
Only self-adjoint operators do. And even then there are questions over whether all do.
 
  • Like
Likes vanhees71 and KevinMcHugh
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

Replies
0
Views
789
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
620
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K