Annoying ellitpical orbit problem

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To determine the speed of a planet at its furthest approach in an elliptical orbit, the conservation of mechanical energy principle can be applied. The total mechanical energy remains constant, meaning the sum of kinetic and potential energy at the closest approach equals that at the furthest point. The relationship between speeds at different distances can be simplified using the ratio of distances, leading to the conclusion that speed decreases as distance increases. The key to solving the problem lies in recognizing that the gravitational potential energy changes inversely with distance, affecting the kinetic energy accordingly. Understanding these principles allows for a more straightforward calculation of the planet's speed at varying distances in its orbit.
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Homework Statement



a planet in elliptical orbit about a star has speed of 100 m/s at its closest approach of 1X 10^10m . what is the speed at its furthest approach of 3X10^10m? What has happened to its total mechanical energy?

Homework Equations





The Attempt at a Solution

 
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I tried to figure out it using mGh+1/2mv^2 = mechanical energy original = mechanical energy final. However, I know there has to be an easier way to do it, using ratios. Could you please tell me the trick?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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