Another Separable Differential Equation

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SUMMARY

The discussion centers on solving the separable differential equation represented by the expression x²y²y' + 1 = y. The user successfully reached the equation -1/x + C = ∫(y²/(y-1))dy but encountered difficulties with the integration of the right-hand side. Suggestions included using polynomial division on y²/(y-1) and applying u-substitution with u = y-1 to simplify the integral. The integration of the resulting quotient and remainder polynomials is confirmed to be straightforward.

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  • Understanding of separable differential equations
  • Knowledge of integration techniques, including polynomial division
  • Familiarity with u-substitution in calculus
  • Basic concepts of differential equations and their solutions
NEXT STEPS
  • Practice solving separable differential equations with varying complexities
  • Learn advanced integration techniques, focusing on polynomial long division
  • Explore u-substitution methods in greater depth
  • Study the properties and applications of differential equations in real-world scenarios
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Students studying calculus, particularly those focusing on differential equations, as well as educators seeking to enhance their teaching methods in integration techniques.

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Homework Statement


Solve the following equation by separating variables.

Homework Equations


x2y2y' +1 = y

The Attempt at a Solution


I have been able to work through the problem to this point:

-1/x + C = int(y2/y-1)dy

I am not sure how to integrate the right hand expression int(y2/y-1)dy
 
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Polynomial division of y2/(y-1) looks like it will work.
 
Last edited:
Have you tried u-substitution with u=y-1?
 
What do you mean by polynomial division?

u-substitution with u = y-1 brings it to int(y^2/u)du, with both y and u variables
 

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