Answer check and explanation(Linear transformation)

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Homework Help Overview

The discussion revolves around finding the standard matrix of a linear transformation defined from R4 to R2. Participants are examining the formulation and representation of the transformation's matrix.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the representation of the transformation matrix, questioning the placement of the vector and the dimensions of the matrix. There are attempts to clarify the structure of the matrix based on the transformation's input and output dimensions.

Discussion Status

There is an ongoing examination of the correct formulation of the transformation matrix. Some participants have provided guidance on the expected dimensions and structure of the matrix, while others are seeking to understand the reasoning behind the transposition of the matrix.

Contextual Notes

Participants note that the transformation is from R4 to R2, which implies specific dimensional requirements for the matrix representation. There is mention of confusion regarding the arrangement of vectors and matrices in the context of linear transformations.

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Homework Statement



Find the standard matrix of the following linear transformation:

T(x1, x2, x3, x4) = (-2 x1 - 5 x2 - 4 x3 - x4, 2 x1 + 2 x2 - 5 x3 + x4)



The Attempt at a Solution



[x1,x2,x3,x4] [-2,2;-5,2;-4,-5;-1,1]
=[-2 x1 - 5 x2 - 4 x3 - x4, 2 x1 + 2 x2 - 5 x3 + x4]



T(e1) = (-2,2)
T(e2) = (-5,2)
T(e3) = (-4,-5)
T(e4) = (-1,1)

A = [-2,-5,-4,-1; 2,2,-5,1]

The answer has been checked to be correct. But I'm not seeing why the standard matrix has to be transposed?
 
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A matrix representing a transformation from ##R^4 \to R^2## would be a 2x4 matrix. The images of the basis vectors give the columns. Nothing is transposed that I see.
 
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negation said:

Homework Statement



Find the standard matrix of the following linear transformation:

T(x1, x2, x3, x4) = (-2 x1 - 5 x2 - 4 x3 - x4, 2 x1 + 2 x2 - 5 x3 + x4)



The Attempt at a Solution



[x1,x2,x3,x4] [-2,2;-5,2;-4,-5;-1,1]
=[-2 x1 - 5 x2 - 4 x3 - x4, 2 x1 + 2 x2 - 5 x3 + x4]
There are two problems with the above:
1. You have your x vector on the wrong side of A (it should be Ax rather than xA), and your matrix is wrong. You have four rows with two columns - it should be two rows with four columns.
negation said:
T(e1) = (-2,2)
T(e2) = (-5,2)
T(e3) = (-4,-5)
T(e4) = (-1,1)
The vectors on the right are all column vectors.
negation said:
A = [-2,-5,-4,-1; 2,2,-5,1]

The answer has been checked to be correct. But I'm not seeing why the standard matrix has to be transposed?
The transformation is T: R4 → R2, so the matrix for T will by 2 X 4 (i.e., two rows with four columns each).
 
Mark44 said:
There are two problems with the above:
1. You have your x vector on the wrong side of A (it should be Ax rather than xA), and your matrix is wrong. You have four rows with two columns - it should be two rows with four columns.
The vectors on the right are all column vectors.
The transformation is T: R4 → R2, so the matrix for T will by 2 X 4 (i.e., two rows with four columns each).

Both of you guys are correct.
 

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