MHB Answer Sequence: 15+30+60+120+240+480+960=1905

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The sequence 15+30+60+120+240+480+960 sums to 1905, and the discussion focuses on determining the $p$th term of the sequence. The quadratic equation derived from the sum is used to find $n$, leading to the formula for the smallest integer greater than $n$. The digits 1-5 repeat in the sequence, allowing for the calculation of the $p$th digit using a modular approach. The conclusion confirms that the $p$th digit for $p=2017$ is 4.
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I did 15+30+60+120+240+480+960 to get 1905, then continued the sequence to get 4. Is this right?
 

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Let's find the $p$th term.

I think what I would do is set:

$$\frac{n(n+1)}{2}=p$$

Now solve for $n$...

$$n(n+1)=2p$$

$$n^2+n-2p=0$$

Using the quadratic formula, and discarding the negative root, we find:

$$n=\frac{-1+\sqrt{8p+1}}{2}$$

We are interested in the smallest integer greater than $n$, so we use

$$\left\lceil \frac{-1+\sqrt{8p+1}}{2}\right\rceil$$

Since the digits 1-5 repeat, then the $p$th digit $D$ is:

$$D(p)=\left\lceil \frac{-1+\sqrt{8p+1}}{2}\right\rceil\mod5$$

And we find:

$$D(2017)=4\quad\checkmark$$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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