- #1

elimeli

- 7

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A set has 200 elements in it. It is partitioned into three subsets so that the second and third subsets have the same number of elements. If four times the number of elements in the second subset is three times as many as in the first, how many elements are in either the second or third subset?

The answer is 120, but I don't understand how to get to that answer.

I equaled 4 nx(2) = 3 nx(1), and so I got that 4nx(2)/3 = nx(1). I then plugged that into 200 = nx(2) + nx(2) + 4nx(2)/3 and got that nx(2)=60. The answer is 120, so I would have to multiply my answer by 2 to get it and I do not understand why, since the answer is asking for either the second or third subset and not the addition of the two.

Can anybody explain?