MHB Answer to Student's Question on Right Angle Triangle

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In a right angle triangle, one angle measures 90 degrees, which is the defining characteristic of this type of triangle. The sum of all interior angles in any triangle is always 180 degrees. Therefore, with one angle at 90 degrees, the remaining two angles must sum to 90 degrees. This means each of the other angles must be greater than 0 degrees and less than 90 degrees. Consequently, no angle in a right triangle can exceed 90 degrees.
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A student ask me the question:
Why the other angles in Right angle triangle can't be more than 90 degrees?
I want to answer him correctly to the question, What Should I Say to Him?
 
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The sum of the interior angles in a triangle is $180^{\circ}$. Given that one angle is $90^{\circ}$ this leaves $90^{\circ}$ for the sum of the other two angles, which means that for either of the other angles, they must be greater than $0^{\circ}$ and less than $90^{\circ}$.
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
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