Anyone explaining 'position equation'?

[text]

Anyone explaining 'position equation'?

 

[phinds]

Anyone explaining 'position equation'?

What form are you talking about? Have you done any research to find the answer?

 

[jim mcnamara]

IF this is from a textbook or homework please give us the whole problem or discussion. We have no way to give you a good answer the way the question was question.

 

[text]

I have no clue as to the 'significance' of the word in question. I googled for it but no use. What in the world is the 'position equation',
aka 'position function'? Please bear with my ignorance, and enlighten me about it. tia. text

 

[phinds]

I have no clue as to the 'significance' of the word in question. I googled for it but no use. What in the world is the 'position equation',
aka 'position function'? Please bear with my ignorance, and enlighten me about it. tia. text

Please re-read post #3. You are not giving enough information.

 

[jtbell]

If you saw 'position equation' on a web page, it would help us a lot if you link to the page so we can see how it is used. If it's in a book, you can copy the paragraph that it appears in.

Words and phrases can have different meanings depending on the context. It would not help you at all if we make a guess and it turns out your source means something different.

 

[text]

http://tinyurl.com/hbyfu9x
Actually, I failed to locate the exact location where I've found the citation
with regard to the question I've raised. Instead, I cite the link above
which will lead to where 's=16t2 + 100...', the same equation I've misplaced.
My question is where 16t2 came from. All the best, text
PS: Specifically, you may find the question in question at page 105, which will open before you.

 

[Ssnow]

$-16t^2$ corresponds to the term $-\frac{1}{2}gt^{2}$ in the law for accelerate motion, here the constant $g$ is not the same of the usual $9,81 m/s^{2}$ but is another ...

 

[maka89]

Newtons second law: z'' = F/m. This gives the acceleration. Integrate twice to get "position equation".

This gives you: z(t) = \frac{1}{2} \frac{F}{m} t^2 + z'(0)t +z(0)

Edit: This gives the same result as Ssnow, assuming F=-mg which is the case for gravitation.

g \approx 32 ft/s^2, so you can see this means the first term is -16. No t term means no initial velocity, and the last term of 100 is the initial height

 

[text]

Newtons second law: z'' = F/m. This gives the acceleration. Integrate twice to get "position equation".

This gives you: z(t) = \frac{1}{2} \frac{F}{m} t^2 + z'(0)t +z(0)

Edit: This gives the same result as Ssnow, assuming F=-mg which is the case for gravitation.

g \approx 32 ft/s^2, so you can see this means the first term is -16. No t term means no initial velocity, and the last term of 100 is the initial height

I missed the secondary education, although I have a college degree in Japanese studies. I am moving forward albeit at a snail pace
to make up for the lost time. Somewhere and somehow I remember seeing the explanation kindly given to me, so that I had an inkling
of the question being related to physics, which has been confirmed.