- #1

JeYo

- 34

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Now, I found the period to be 24hr, and the value of g to be 0.223m/s/s. But I cannot seem to find a formula to

*correctly*calculate the apparent weight of the satellite with this information.

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- Thread starter JeYo
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- #1

JeYo

- 34

- 0

Now, I found the period to be 24hr, and the value of g to be 0.223m/s/s. But I cannot seem to find a formula to

- #2

JeYo

- 34

- 0

I have already tried these equations: W = mω^2r and W = ma, with a being 0.223 m/s/s

- #3

dynamicsolo

Homework Helper

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Now, I found the period to be 24hr, and the value of g to be 0.223m/s/s. But I cannot seem to find a formula tocorrectlycalculate the apparent weight of the satellite with this information.

Trick question! I also get your answer for the local gravitational acceleration of 0.224 m/(sec^2). However, keep in mind that the local "weight force", which is the magnitude of the gravitational force acting on the satellite,

Think about how weight is perceived. When you stand on a scale, what you read off is

If you jumped out of a high window (don't do it!), you would indeed have a weight force acting on you, accelerating you toward the Earth (while the Earth also immeasurably accelerates toward you), but what would you

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