Apparent weight of body immersed in liquid

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SUMMARY

The discussion centers on the apparent weight of a body immersed in liquid and the relationship between upthrust and density. Three scenarios are analyzed: (a) where the body sinks, (b) where it floats fully immersed, and (c) where it floats while displacing liquid equal to its weight. The conclusions drawn confirm that the order of densities is (\rho_L)_c > (\rho_L)_b > (\rho_L)_a, and emphasize that the upthrust formula U = \rho_L V_B g is only valid when the body is fully immersed. The importance of understanding the depth of immersion is also highlighted.

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  • Understanding of buoyancy and Archimedes' principle
  • Familiarity with the concepts of density and upthrust
  • Knowledge of the relationship between weight and volume in fluids
  • Basic graph interpretation skills in physics contexts
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brotherbobby
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Homework Statement
A rectangular block is pushed face-down into three liquids, in turn. The apparent weight ##W_{\text{app}}## of the block versus the depth ##h## in the three liquids is plotted in the graph shown below.

Rank the liquids according to their greatest weight per unit volume, greatest first.
Relevant Equations
Apparent weight of a body partially (or wholly) immersed in liquid ##w'_B = w_B - U## where ##w_B## is the (original) weight of the body and ##U## is the upthrust which is equal to the weight of the liquid diplaced : ##U = \Delta W_L = \rho_L V_B g##. Here ##\rho_L \; \text{and} \; V_B## are the density of the liquid and the volume of the body, respectively.
1580206450466.png


I have to assume that ##h## is the height of the body. The graph above shows how the apparent weight of the body changes as it is immersed into the liquid.

In (a), after immersing the whole height of the body, the apparent weight ##W_{\text{app}} > 0##. Hence the upthrust ##U < w_B \Rightarrow (\rho_L)_a < \rho _B##. If released, the body would sink into the liquid (a).

In (b), the apparent weight of the body is 0 by the time it is wholly immersed : ##W_{\text{app}} = 0##. Hence the upthrust ##U = w_B \Rightarrow (\rho_L)_b = \rho _B##. If released, the body would just sink into the liquid (b), and float entirely immersed.

In (c), the apparent weight of the body is negative by the time it is wholly immersed : ##W_{\text{app}} < 0##. Hence the upthrust ##U > w_B \Rightarrow (\rho_L)_c > \rho _B##. If released, the body would float in the liquid, displacing an amount of liquid equal to its weight. The (height) depth of the body above the liquid is not ##h## but the height corresponding to where the line in (c) cuts the ##x## axis, where it's apparent weight is zero.

From above, we find that ##\boxed{\color{red}{(\rho_L)_c > (\rho_L)_b > (\rho_L)_a}}##.

Is my answer correct?
 
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Apart from assuming that h is the height of the body, when you are told it is the depth of immersion, yes. You are not told the height of the body, so you don't know at what point it will be totally immersed, but the order of the densities is correct.

Also U = ρLVBg is only correct when the body is fully immersed. If it is partially immersed, the volume you should use is the volume of that part of the body which is immersed.
Note that this means that at the point where the body becomes totally immersed, the slope of the lines in your graph changes to become horizontal. This point is not reached in the experiment described. But that doesn't affect your right answer to the question.
 
mjc123 said:
Apart from assuming that h is the height of the body, when you are told it is the depth of immersion, yes. You are not told the height of the body, so you don't know at what point it will be totally immersed, but the order of the densities is correct.

Also U = ρLVBg is only correct when the body is fully immersed. If it is partially immersed, the volume you should use is the volume of that part of the body which is immersed.
Note that this means that at the point where the body becomes totally immersed, the slope of the lines in your graph changes to become horizontal. This point is not reached in the experiment described. But that doesn't affect your right answer to the question.

Yes thank you. Calling the upthrust ##U = \rho_L V_B g## is only valid if the body is wholly immersed, or else the body's entire volume does not 'engage' with the liquid to displace it. Hence, upthrust is a function of the depth of a body immersed, so we can write I suppose ##U= U(d)##. It's a small point that books miss out on.

Yes, the upthrust of a liquid on a body is independent of position if the body was wholly immersed into it. Hence, as you said, the graphs in my question would be horizontal beyond ##h##.

Thank you, those were important points.
 
How does one know that in liquid a, the object sinks, in liquid b, it floats, and in liquid c it floats and displaces liquid equal to its own weight? I couldn't tell by looking at the graph. Thank you in advance!
 
Welcome to PF.

ducsinhsn said:
How does one know that in liquid a, the object sinks, in liquid b, it floats, and in liquid c it floats and displaces liquid equal to its own weight? I couldn't tell by looking at the graph. Thank you in advance!
What are your thoughts on that?
 

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