This question is continued from a problem that I have already solved. This is what I know from the previous problem that will be helpful:
r= 0.20 m
roh of solid sphere= 850 kg/m^3
mass sphere= 3.94 x 10 ^-5 kg
I also have 2 apparent weights that I solved for when the tension in the system is
a. 150 N ----> Normal force (apparent weight) Fn = -1.49 x 10^2
b. 0 N -----> Fn = -3.86 x 10^-4 N
(Hopefully those are correct)
Now- the problem I came for help on:
A room is partially filled with water with a sphere in it and the sphere is on a scale. What percentage of the sphere must be immersed in the water in order to achieve the same apparent weights as above (a and b).
And- What percentage of the sphere must be immersed to achieve an apparent weight of zero?
% immersed = V immersed/ V total = roh obj/roh fluid
Bouyant force (Fb) = roh x V x g
Fn = mg + ma (a = O)
And from a full body diagram I have this:
Fn + Fb - mg = ma (whch is zero)
The Attempt at a Solution
Well....I really am not sure what to do. One fact that I know and I think will help me is that if an object is say 90% underwater, then the roh of the object is 90% of the fluid....
I need a kick in the right direction please.