- #1
brotherbobby
- 614
- 151
- Homework Statement
- A rectangular block is pushed face-down into three liquids, in turn. The apparent weight ##W_{\text{app}}## of the block versus the depth ##h## in the three liquids is plotted in the graph shown below.
Rank the liquids according to their greatest weight per unit volume, greatest first.
- Relevant Equations
- Apparent weight of a body partially (or wholly) immersed in liquid ##w'_B = w_B - U## where ##w_B## is the (original) weight of the body and ##U## is the upthrust which is equal to the weight of the liquid diplaced : ##U = \Delta W_L = \rho_L V_B g##. Here ##\rho_L \; \text{and} \; V_B## are the density of the liquid and the volume of the body, respectively.
I have to assume that ##h## is the height of the body. The graph above shows how the apparent weight of the body changes as it is immersed into the liquid.
In (a), after immersing the whole height of the body, the apparent weight ##W_{\text{app}} > 0##. Hence the upthrust ##U < w_B \Rightarrow (\rho_L)_a < \rho _B##. If released, the body would sink into the liquid (a).
In (b), the apparent weight of the body is 0 by the time it is wholly immersed : ##W_{\text{app}} = 0##. Hence the upthrust ##U = w_B \Rightarrow (\rho_L)_b = \rho _B##. If released, the body would just sink into the liquid (b), and float entirely immersed.
In (c), the apparent weight of the body is negative by the time it is wholly immersed : ##W_{\text{app}} < 0##. Hence the upthrust ##U > w_B \Rightarrow (\rho_L)_c > \rho _B##. If released, the body would float in the liquid, displacing an amount of liquid equal to its weight. The (height) depth of the body above the liquid is not ##h## but the height corresponding to where the line in (c) cuts the ##x## axis, where it's apparent weight is zero.
From above, we find that ##\boxed{\color{red}{(\rho_L)_c > (\rho_L)_b > (\rho_L)_a}}##.
Is my answer correct?