Apparent weight of body immersed in liquid

In summary, the conversation discusses the apparent weight of a body as it is immersed into different liquids. The upthrust and density of the liquids are also considered. The expert summarizer notes that the order of densities is correct and that the volume used in the upthrust equation depends on whether the body is fully immersed or partially immersed. They also mention that the graph's lines change to become horizontal when the body is fully immersed and that the upthrust is independent of position in this case. The expert also mentions that the body sinks in liquid a, floats in liquid b, and displaces an equal amount of liquid in liquid c, based on the information given in the conversation.
  • #1
brotherbobby
614
151
Homework Statement
A rectangular block is pushed face-down into three liquids, in turn. The apparent weight ##W_{\text{app}}## of the block versus the depth ##h## in the three liquids is plotted in the graph shown below.

Rank the liquids according to their greatest weight per unit volume, greatest first.
Relevant Equations
Apparent weight of a body partially (or wholly) immersed in liquid ##w'_B = w_B - U## where ##w_B## is the (original) weight of the body and ##U## is the upthrust which is equal to the weight of the liquid diplaced : ##U = \Delta W_L = \rho_L V_B g##. Here ##\rho_L \; \text{and} \; V_B## are the density of the liquid and the volume of the body, respectively.
1580206450466.png


I have to assume that ##h## is the height of the body. The graph above shows how the apparent weight of the body changes as it is immersed into the liquid.

In (a), after immersing the whole height of the body, the apparent weight ##W_{\text{app}} > 0##. Hence the upthrust ##U < w_B \Rightarrow (\rho_L)_a < \rho _B##. If released, the body would sink into the liquid (a).

In (b), the apparent weight of the body is 0 by the time it is wholly immersed : ##W_{\text{app}} = 0##. Hence the upthrust ##U = w_B \Rightarrow (\rho_L)_b = \rho _B##. If released, the body would just sink into the liquid (b), and float entirely immersed.

In (c), the apparent weight of the body is negative by the time it is wholly immersed : ##W_{\text{app}} < 0##. Hence the upthrust ##U > w_B \Rightarrow (\rho_L)_c > \rho _B##. If released, the body would float in the liquid, displacing an amount of liquid equal to its weight. The (height) depth of the body above the liquid is not ##h## but the height corresponding to where the line in (c) cuts the ##x## axis, where it's apparent weight is zero.

From above, we find that ##\boxed{\color{red}{(\rho_L)_c > (\rho_L)_b > (\rho_L)_a}}##.

Is my answer correct?
 
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  • #2
Apart from assuming that h is the height of the body, when you are told it is the depth of immersion, yes. You are not told the height of the body, so you don't know at what point it will be totally immersed, but the order of the densities is correct.

Also U = ρLVBg is only correct when the body is fully immersed. If it is partially immersed, the volume you should use is the volume of that part of the body which is immersed.
Note that this means that at the point where the body becomes totally immersed, the slope of the lines in your graph changes to become horizontal. This point is not reached in the experiment described. But that doesn't affect your right answer to the question.
 
  • #3
mjc123 said:
Apart from assuming that h is the height of the body, when you are told it is the depth of immersion, yes. You are not told the height of the body, so you don't know at what point it will be totally immersed, but the order of the densities is correct.

Also U = ρLVBg is only correct when the body is fully immersed. If it is partially immersed, the volume you should use is the volume of that part of the body which is immersed.
Note that this means that at the point where the body becomes totally immersed, the slope of the lines in your graph changes to become horizontal. This point is not reached in the experiment described. But that doesn't affect your right answer to the question.

Yes thank you. Calling the upthrust ##U = \rho_L V_B g## is only valid if the body is wholly immersed, or else the body's entire volume does not 'engage' with the liquid to displace it. Hence, upthrust is a function of the depth of a body immersed, so we can write I suppose ##U= U(d)##. It's a small point that books miss out on.

Yes, the upthrust of a liquid on a body is independent of position if the body was wholly immersed into it. Hence, as you said, the graphs in my question would be horizontal beyond ##h##.

Thank you, those were important points.
 
  • #4
How does one know that in liquid a, the object sinks, in liquid b, it floats, and in liquid c it floats and displaces liquid equal to its own weight? I couldn't tell by looking at the graph. Thank you in advance!
 
  • #5
Welcome to PF.

ducsinhsn said:
How does one know that in liquid a, the object sinks, in liquid b, it floats, and in liquid c it floats and displaces liquid equal to its own weight? I couldn't tell by looking at the graph. Thank you in advance!
What are your thoughts on that?
 

1. What is the apparent weight of a body immersed in liquid?

The apparent weight of a body immersed in liquid is the weight of the body when it is submerged in the liquid. It is different from the actual weight of the body due to the upward force exerted by the liquid, known as buoyancy.

2. How is the apparent weight of a body immersed in liquid calculated?

The apparent weight of a body immersed in liquid is calculated by subtracting the weight of the displaced liquid from the actual weight of the body. This can be calculated using the formula: Apparent weight = Actual weight - Buoyant force.

3. What factors affect the apparent weight of a body immersed in liquid?

The apparent weight of a body immersed in liquid is affected by the density of the liquid, the volume of the body, and the gravitational force acting on the body. It is also affected by the shape and size of the body, as well as the depth at which it is submerged.

4. How does the apparent weight of a body immersed in liquid change with depth?

The apparent weight of a body immersed in liquid increases as the depth of immersion increases. This is because the pressure exerted by the liquid increases with depth, resulting in a greater buoyant force that counteracts the weight of the body.

5. How does the apparent weight of a body immersed in liquid differ from its weight in air?

The apparent weight of a body immersed in liquid is less than its weight in air due to the buoyant force exerted by the liquid. This is because the liquid exerts an upward force on the body, reducing its effective weight. In contrast, the weight of a body in air is only affected by the force of gravity.

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