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ucody0911

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- Homework Statement
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- Relevant Equations
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Hello ,all

I'm calculating the force that required to push steel rod up 50 cm into water filled steel tank . pls see picture . If i exclude negligible friction force (which is friction between steel rod and water sealing gaskets )

Total Force = Force to lift 40 kg rod + Fluid Force exerted on horizontal surface of rod

so, 1. Force to lift 40 kg rod = 40 x 9.81 = 392.4 N

2 . Fluid Force exerted on horizontal surface of rod - F= PxA

- hydrostatic pressure of 15 m high water P = 147000 N/m2

- surface area of 10 cm diameter rod A = 0.00785 m2

F= 147000 x 0.00785 = 1154 N

Total Force = 392.4 +1154 = 1546.4 N

pls help me , is this correct ? any other forces missed into calculation ?

I'm calculating the force that required to push steel rod up 50 cm into water filled steel tank . pls see picture . If i exclude negligible friction force (which is friction between steel rod and water sealing gaskets )

Total Force = Force to lift 40 kg rod + Fluid Force exerted on horizontal surface of rod

so, 1. Force to lift 40 kg rod = 40 x 9.81 = 392.4 N

2 . Fluid Force exerted on horizontal surface of rod - F= PxA

- hydrostatic pressure of 15 m high water P = 147000 N/m2

- surface area of 10 cm diameter rod A = 0.00785 m2

F= 147000 x 0.00785 = 1154 N

Total Force = 392.4 +1154 = 1546.4 N

pls help me , is this correct ? any other forces missed into calculation ?

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