MHB Apply Binomial Theorem: Expand (x-2y)^3

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To expand the binomial expression (x - 2y)^3 using the binomial theorem, the formula is applied as (a + b)^n = Σ(n choose r) a^(n-r) b^r. Rewriting (x - 2y) as (x + (-2y)), the expansion results in the sum of terms involving coefficients from the binomial coefficients. The final expanded form is x^3 - 6x^2y + 12xy^2 - 8y^3. This demonstrates the application of the binomial theorem to expand the given expression accurately.
MarkFL
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Here is the question:

How to expand this binomial expansion?


a.) (x - 2y)^3

with the equation:

(n over r) x [a^(n-r)] x (b^r)

Thank you!

I have posted a link there to this topic so the OP can see my work.
 
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Hello Person,

The binomial theorem may be stated as:

$$(a+b)^b=\sum_{r=0}^{n}{n \choose r}a^{n-r}b^r$$

And so, for the given binomial to be expanded, we have:

$$(x-2y)^3=(x+(-2y))^3=\sum_{r=0}^{3}{3 \choose r}x^{n-r}(-2y)^r$$

$$(x-2y)^3={3 \choose 0}x^3(-2y)^0+{3 \choose 1}x^2(-2y)^1+{3 \choose 2}x^1(-2y)^2+{3 \choose 3}x^0(-2y)^3$$

$$(x-2y)^3=1\cdot x^3\cdot1+3x^2(-2y)+3x(-2y)^2+1\cdot1\cdot(-2y)^3$$

$$(x-2y)^3=x^3-6x^2y+12xy^2-8y^3$$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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