Applying Gauss's Lemma to Calculate Legendre Symbol (6/13)

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Use Gauss Lemma (Number theory) to calculate the Legendre Symbol [tex](\frac{6}{13})[/tex].

I know how to use Gauss Lemma. However we use the book: Ireland and Rosen. They define Gauss Lemma as:

[tex](\frac{a}{p})=(-1)^n[/tex]. They say: Let [tex]\pm m_t[/tex] be the least residue of [tex]ta[/tex], where [tex]m_t[/tex] is positive. As [tex]t[/tex] ranges between 1 and [tex]\frac{(p-1)}{2}[/tex], n is the number of minus signs that occur in this way. I don't understand how to use this form of Gauss's Lemma
 
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What are [itex]a[/itex] and [itex]p[/itex] in this case? What does that make [itex]\frac{(p-1)}{2}[/itex] ? What does that make the least residue of [itex]ta[/itex] in this case?
 
Could you be more specific, I really do not know how to use this version of Gauss's Lemma. Could you show me some steps on how to start it this way?
 
You want to use the lemma for [itex]\left( \frac{6}{13} \right)[/itex], which means you want an "a" and "p" such that [itex]\left( \frac{a}{p} \right) = \left( \frac{6}{13} \right)[/itex] where "p" is a prime...surely you can think of at least one "a" and one "p" for which this will hold true?