Applying KVL: Understanding the Process and Confusions

  • Thread starter Thread starter sciman
  • Start date Start date
  • Tags Tags
    Application Kvl
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
sciman
Messages
24
Reaction score
1
hello

what is the process to apply KVL exactly?

we know nothing in a loop, apart from that it consists of 2 batteries with known polarity and 2 resistors.

what do we do?

we assign arbitrarily the currents to each of the branches that compose the loop? and then we assign polarities to the resistors?

or we assign arbitrarily polarities to the resistors in the loop and apply kvl based on that and if we find negative values, we just invert the polarity?

I am a bit confused

To give you an example:
upload_2015-4-15_14-28-19.png


1) according to the first method (we take resistor polarities based on the arbitrarily taken currents)
in left loop, we have V1-Vr3-Vr1=0
in right loop, we have V2-Vr2+Vr3=0
2) according to the second method (we assign polarities of resistors arbitrarily)
in left loop, we have V1-Vr3-Vr1=0
in right loop, we have V2-Vr2+Vr3=0

which are the same, but the website of this example gives:
0cbb994040dab97570b92f9b9749960b.png

and
4321cdc46d8988dee94d4e54a0d32e97.png


WHICH IS DIFFERENT!thanks
 
Last edited:
Physics news on Phys.org
sciman said:
hello

what is the process to apply KVL exactly?

we know nothing in a loop, apart from that it consists of 2 batteries with known polarity and 2 resistors.

what do we do?

we assign arbitrarily the currents to each of the branches that compose the loop? and then we assign polarities to the resistors?

or we assign arbitrarily polarities to the resistors in the loop and apply kvl based on that and if we find negative values, we just invert the polarity?

I am a bit confused

To give you an example:
View attachment 82039

1) according to the first method (we take resistor polarities based on the arbitrarily taken currents)
in left loop, we have V1-Vr3-Vr1=0
in right loop, we have V2-Vr2+Vr3=0
2) according to the second method (we assign polarities of resistors arbitrarily)
in left loop, we have V1-Vr3-Vr1=0
in right loop, we have V2-Vr2+Vr3=0

which are the same, but the website of this example gives:
0cbb994040dab97570b92f9b9749960b.png

and
4321cdc46d8988dee94d4e54a0d32e97.png


WHICH IS DIFFERENT!thanks
I think it's just a typo.

He later writes:
a94bdc8bc3c8f2088e7080f82db570a4.png


and
67ea64f45c29bdc54996286d5d07072b.png


which implies using opposite signs for VR3 .