Luggage is transported from one location to another in an airport by a conveyor belt. At a certain location, the belt moves down an incline that makes an angle of 2.5 degrees with the horizontal. Assume that with such a slight angle there is no slipping of the luggage. Determine the magnitude and direction of the frictional force by the belt on a box weighing 69 N when the box is on the inclined portion of the belt for the following situations:(adsbygoogle = window.adsbygoogle || []).push({});

(a) The belt is stationary.

(b) The belt has a speed of 0.65 m/s that is constant.

(c) The belt has a speed of 0.65 m/s that is increasing at a rate of 0.20 m/s^2.

(d) The belt has a speed of 0.65 m/s that is decreasing at a rate of 0.20 m/s^2.

(e) The belt has a speed of 0.65 m/s that is increasing at a rate of 0.57 m/s^2.

So, I was able to figure out the answer to a, and b is 3.00 N, just by doing 69 sin 2.5. So... what would I do for the other 3? c and d are similar, so if I can find one, I better be able to find the other. Still need to find d as well. Ideas? Thanks!

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# Homework Help: Applying Newtons Laws to solve this

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