Luggage is transported from one location to another in an airport by a conveyor belt. At a certain location, the belt moves down an incline that makes an angle of 2.5 degrees with the horizontal. Assume that with such a slight angle there is no slipping of the luggage. Determine the magnitude and direction of the frictional force by the belt on a box weighing 69 N when the box is on the inclined portion of the belt for the following situations: (a) The belt is stationary. (b) The belt has a speed of 0.65 m/s that is constant. (c) The belt has a speed of 0.65 m/s that is increasing at a rate of 0.20 m/s^2. (d) The belt has a speed of 0.65 m/s that is decreasing at a rate of 0.20 m/s^2. (e) The belt has a speed of 0.65 m/s that is increasing at a rate of 0.57 m/s^2. So, I was able to figure out the answer to a, and b is 3.00 N, just by doing 69 sin 2.5. So... what would I do for the other 3? c and d are similar, so if I can find one, I better be able to find the other. Still need to find d as well. Ideas? Thanks!