Approximatly 5% of each exhaled breath is carbon dioxide

Click For Summary
Approximately 5% of each exhaled breath consists of carbon dioxide, with normal lung capacity estimated at half a liter. To find the mass difference between inhaled and exhaled breaths, one must calculate the amount of oxygen converted to carbon dioxide during respiration. The discussion highlights the need to determine the weights of these gases using their molar masses. Participants express uncertainty about the calculations and the necessary steps to arrive at the solution. Understanding the conversion of oxygen to carbon dioxide is crucial for solving the problem.
matt_crouch
Messages
157
Reaction score
1

Homework Statement



In normal breathing conditions approximatly 5% of each exhaled breath is carbon dioxide. Given this informartion and neglecting any difference in water-vapor content estimate the typical difference in mass between an inhaled breath and an exhaled breath. assume one lungs capacity is about half a litre and that 20 % of the air that is breathed in is oxygen.


Homework Equations



n=m/mr

The Attempt at a Solution



not really sure where to start for this one
 
Physics news on Phys.org


It tells you how much oxygen is breathed in on each breath
5% of the total amount of air is turned into CO2
So work out how much oxygen is turned into CO2

Then we can work out how much this volume of O2 and CO2 weigh
 


How do you work out how much the volume of these gases weigh? Would you need to look up extra information such as molar mass of 02 and C02?
 


mgb_phys said:
It tells you how much oxygen is breathed in on each breath
5% of the total amount of air is turned into CO2
So work out how much oxygen is turned into CO2

Then we can work out how much this volume of O2 and CO2 weigh

1/4 of the O2 is turned into CO2 and I'm not sure what i have to do now?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 16 ·
Replies
16
Views
3K
Replies
24
Views
11K
  • · Replies 12 ·
Replies
12
Views
87K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
4K
Replies
15
Views
4K
Replies
5
Views
18K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K