AQA physics paper question: Where is the potential zero near these charges?

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bonbon22
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Homework Statement
The diagram shows two charges, +4 µC and -16 µC, 120 mm apart. What is the distance from the +4 µC
charge to the point between the two charges, where the resultant electric potential is zero?
A 24 mm
B 40 mm
C 80 mm
D 96 mm
Relevant Equations
f=kq1q2/r^2
This question is a bit werid because would there be a resulatant electric potential equal to zero as we have a positive and negative charge in which case there's no neutral point. As E1-E2 , they have to be acting in oppostie directions , in this case would they be acting in the same direction.
 
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bonbon22 said:
This question is a bit werid because would there be a resulatant electric potential equal to zero as we have a positive and negative charge in which case there's no neutral point. As E1-E2 , they have to be acting in oppostie directions , in this case would they be acting in the same direction.

Why do you think zero potential implies zero electric field (at a given point)?
 
PeroK said:
Why do you think zero potential implies zero electric field (at a given point)?
i think their is no neutral point but apparently their is, but these two charges are opposite yet the questions suggested theirs a neutral point so i don't quite understand. i understand how to get the answer of 24 mm.
 
bonbon22 said:
i think their is no neutral point but apparently their is, but these two charges are opposite yet the questions suggested theirs a neutral point so i don't quite understand. i understand how to get the answer of 24 mm.

What do you mean by a "neutral" point? Where the field is zero? Or, where the potential is 0?

Note that you can always add a constant to the potential, so that the value of the potential has no physical significance in itself.
 
PeroK said:
What do you mean by a "neutral" point? Where the field is zero? Or, where the potential is 0?

Note that you can always add a constant to the potential, so that the value of the potential has no physical significance in itself.
i mean that the when you have two positive or negative charges inbetween there's a point where F1= F2
the neutral point, in this case as the forces are acting in together its f1+f2, but would their potentials not also act in the same direction? hence no neutral point. to get the answer 24 mm i minused the potentials.
 
bonbon22 said:
i mean that the when you have two positive or negative charges inbetween there's a point where F1= F2
the neutral point, in this case as the forces are acting in together its f1+f2, but would their potentials not also act in the same direction? hence no neutral point. to get the answer 24 mm i minused the potentials.

A potential has no direction. It's not a vector. The potential and the field are very different things.
 
PeroK said:
A potential has no direction. It's not a vector. The potential and the field are very different things.
So why does minusing the potentials give me the answer ? I assumed as f = k q1q2/r^2 and potential has the equation v=kq1/r that's they are similar , different from graviational where its mass which can only have a magnitute but charge can be positive and negative right? so the potential can be positive and negative am i missing something?
 
bonbon22 said:
So why does minusing the potentials give me the answer ? I assumed as f = k q1q2/r^2 and potential has the equation v=kq1/r that's they are similar , different from graviational where its mass which can only have a magnitute but charge can be positive and negative right? so the potential can be positive and negative am i missing something?

A sign is not a direction. You have found a point where the potential is 0. That says nothing about the field at that point.

Try calculating the electric field at that point.