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blaphysics
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A solid weights 260N in air, 240N in water of a fluid density 1000kg/m^3, and 250N in oil
Determine the relative density of the solid and of the oil
I think I have already worked out the density of the solid:
Weight of water displaced = 260N - 240N = 20N
20N / 9.8 = 2.0408kg
Water density = 1kg per litre, so there is 2.0408 litres or 2040.8 cm^3
Mass of solid = 260N / 9.81 = 26.5kg
Mass/ Vol = Density = 26.5 / 2040.8 = 0.01299 kg/cm^3
If this is correct so far, how would I go about working the density of the oil, and are these figures measures of "relative density", which I understand to just be a comparison to the density of water?
Thank you!
Determine the relative density of the solid and of the oil
I think I have already worked out the density of the solid:
Weight of water displaced = 260N - 240N = 20N
20N / 9.8 = 2.0408kg
Water density = 1kg per litre, so there is 2.0408 litres or 2040.8 cm^3
Mass of solid = 260N / 9.81 = 26.5kg
Mass/ Vol = Density = 26.5 / 2040.8 = 0.01299 kg/cm^3
If this is correct so far, how would I go about working the density of the oil, and are these figures measures of "relative density", which I understand to just be a comparison to the density of water?
Thank you!