- #1

huffy

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## Homework Statement

One way of moving a large undersea rock or mooring is to fasten a closed, empty oil drum to the rock while at low tide. As the tide comes in the drum is drawn down into the water increasing the buoyant foce acting on the system of the rock and drum. Suppose a cylindrical drum of radius 25 cm, length 100cm, and mass 20kg is used. What is the maximum mass of a rock (of density 5.0 x10^3) that the drum can lift from the bottom? Assume the density of sea water is the same as that of pure water.

http://imgur.com/Y4Qrhjq

http://imgur.com/2wD4OpR

## Homework Equations

PfVs=PoVo

## The Attempt at a Solution

So to solve this I am trying to use archimedes principle which is the density of a fluid times the volume submerged=the density of the system times the volume of the system (PfVs=PoVo). I know That Pf=1000kg/m^3 because its pure water and I know that the Po is approx 102.4 because i can use m=PV to find the density of the drum and add it to the density of the rock. I also know that the volume of the system is Vdrum+Vrock.

I end up with the formula 1000kg/m^3*Vsubmerged=102.04(0.196+(Mrock/5.0x10^3) where 0.196 is the volume of the drum and 5.0x10^3 is the density of the rock.

Rearranged I get that Mrock=(1000kg/m^3-20.04/102.04)*5.0x10^3

What do i need to do to find the volume of the submerged?