Are fractional polynomials linearly independent?

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SUMMARY

The discussion centers on the linear independence of fractional polynomials of the form \{ x^{\frac{n}{m}} \}_{n=0}^{\infty} for a fixed m. It is established that any linear combination of a finite number of these functions can be expressed as a polynomial equation, specifically a_ny^n + a_{n-1}y^{n-1} + ... + a_1y = 0, where y = x^{\frac{1}{m}}. Since a polynomial of degree n has exactly n roots, the existence of a non-trivial linear combination equating to zero is impossible, confirming that these fractional polynomials are indeed linearly independent.

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i.e., does the set of functions of the form,

\{ x^{\frac{n}{m}}\}_{n=0}^{\infty} for some fixed m produce a linearly independent set? Either way, can you give a brief argument why or why not?

Just curious :)
 
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If you have any linear combination between a finite number of these elements, this relation can be written as

a_ny^n+a_{n-1}y^{n-1}+...+a_1y = 0

where y = x^{\frac{1}{m}} and a_n is non-zero. However, a polynomial of degree n has exactly n zeroes, which means that this is impossible.
 
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