Are My Calculations Correct for this Complex Circuit?

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Homework Statement


circuit.jpg

Solve for all voltage drops and currents at the resistors and battery


Homework Equations


V=IR
RT=R1+R2+...+Rn
1/RT=1/R1+1/R2+...+1/Rn
IT=I1+I2+...+In

The Attempt at a Solution



I just wanted to check if my solution is correct

------Voltage----Current----Resistance
R1-----150--------3.75---------40
R2-----150--------3.75---------40
R3-----45---------0.75---------60
R4-----15-----------3------------5
R5-----30-----------2-----------15
R6-----20-----------1-----------20
R7-----10-----------1-----------10
Total---345--------3.75---------92
 
Last edited:
on Phys.org
This would be easier if the resistor numbers and current directions would be marked in the diagram...

You can simply check Kirchhoff's laws for every node and loop as cross-check.
 
Is there something about V that you seem to know and we don't ?
So far I can only stamp an approval stamp on R6 and R7 (they happen to be the only ones with 10 and 20 Ohm).
 
Because the voltage drop though resistors R6(20ohms) and R7(10ohms) causes a total voltage drop of 30V any parallel circuits to it will also have a voltage drop of 30 V. therefore R5(15ohms) must have a voltage drop of 30V.
 
BvU said:
Is there something about V that you seem to know and we don't ?
So far I can only stamp an approval stamp on R6 and R7 (they happen to be the only ones with 10 and 20 Ohm).

Because the voltage drop though resistors R6(20ohms) and R7(10ohms) causes a total voltage drop of 30V any parallel circuits to it will also have a voltage drop of 30 V. therefore R5(15ohms) must have a voltage drop of 30V.
 
The voltage drops of 30 V on the right side are fine, but the voltage of the voltage source is unclear.
 
The total is what I calculated the voltage source to be but I'm not sure its correct.
 
Which total?
You cannot solve this problem if you don't know the voltage drop at the voltage source.
 
mfb said:
The voltage drops of 30 V on the right side are fine, but the voltage of the voltage source is unclear.
It appears the ammeter is displaying a reading of 1.0A, meaning there is sufficient information to determine V.
 
  • #10
My mistake. I saw a current source instead of an ammeter. :redface:
 
  • #11
BvU said:
My mistake. I saw a current source instead of an ammeter. :redface:
Same here.
Okay, then it is fine.
 
  • #12
So herewith a stamp of approval goes to post #1. And now I run the risk of being chastized by the spirits that float over and guard PF: the forum isn't really intended for that kind of thing at all. With good reasons.
Still, it was nice to look into this exercise...
 
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